–sin θ is not equal to :
A
cos 
B
cos 
C
sin ( θ – π )
D
sin ( π + θ )
Text Solution
Verified by ExpertsThe correct answer is:
D
cos 
→ II equivelent
∴ cos 
= –sin θ [cos in II equivelent function – ve]
sin ( θ – π ) = sin[–( π – θ )] = –sin( π – θ )
= – sin θ
sin( π + θ ) = – sin θ [sin f n is –ve in III equivelent]
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